2x^2+26x=-72

Solution for 2x^2+26x=-72 equation:

2x^2+26x=-72

We move all terms to the left:

2x^2+26x-(-72)=0

We add all the numbers together, and all the variables

2x^2+26x+72=0

a = 2; b = 26; c = +72;
Δ = b2-4ac
Δ = 262-4·2·72
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-10}{2*2}=\frac{-36}{4}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+10}{2*2}=\frac{-16}{4}
=-4
$